If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x+1/x^2+1=7/12
We move all terms to the left:
2x+1/x^2+1-(7/12)=0
Domain of the equation: x^2!=0We add all the numbers together, and all the variables
x^2!=0/
x^2!=√0
x!=0
x∈R
2x+1/x^2+1-(+7/12)=0
We get rid of parentheses
2x+1/x^2+1-7/12=0
We calculate fractions
There is no solution for this equation
| 4(2x-3)=x^2 | | 11x-3x-14x=-64-12 | | 11x-46-6x=54 | | 7+x^2=16 | | 10w2=7w+6 | | 2=k/19-4 | | 3.5+j=5 | | 3(q+1)=27 | | 0.5x-1/2=1/2 | | 70=7(r+4) | | 0.5x=1/2=1/2 | | k)2-5=13 | | -6w+-18=42 | | -32+3d=52 | | 8=8(q-92) | | 7+2-5=12x+3x-9x | | 9(u-87)=81 | | 72/x=18 | | 4-5=(-4g+3) | | 2x+3x-4=6x-9x+3 | | -3+6-2j=j-3 | | k-6=2(4+k) | | 6(r+9)=84 | | x-(x*30/100)=70 | | S2.6(5.5p–12.4)=127.92 | | 4=(-7+5d)-7d | | K×3k×6=0 | | 20=x+(-12) | | 3(2x+1)+×=-39 | | -5=(3-2b)+3b | | 0.5(12x+12)=3/4(8x+8) | | 17x-8=25 |